8w^2+8w+9w=2w=2

Solution for 8w^2+8w+9w=2w=2 equation:

8w^2+8w+9w=2w=2

We move all terms to the left:

8w^2+8w+9w-(2w)=0

We add all the numbers together, and all the variables

8w^2+15w=0

a = 8; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·8·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*8}=\frac{-30}{16}
=-1+7/8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*8}=\frac{0}{16}
=0
$